Integrand size = 20, antiderivative size = 72 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=-\frac {a^5 c^4}{4 x^4}+\frac {a^4 b c^4}{x^3}-\frac {a^3 b^2 c^4}{x^2}-\frac {2 a^2 b^3 c^4}{x}+b^5 c^4 x-3 a b^4 c^4 \log (x) \]
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Time = 0.02 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {76} \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=-\frac {a^5 c^4}{4 x^4}+\frac {a^4 b c^4}{x^3}-\frac {a^3 b^2 c^4}{x^2}-\frac {2 a^2 b^3 c^4}{x}-3 a b^4 c^4 \log (x)+b^5 c^4 x \]
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Rule 76
Rubi steps \begin{align*} \text {integral}& = \int \left (b^5 c^4+\frac {a^5 c^4}{x^5}-\frac {3 a^4 b c^4}{x^4}+\frac {2 a^3 b^2 c^4}{x^3}+\frac {2 a^2 b^3 c^4}{x^2}-\frac {3 a b^4 c^4}{x}\right ) \, dx \\ & = -\frac {a^5 c^4}{4 x^4}+\frac {a^4 b c^4}{x^3}-\frac {a^3 b^2 c^4}{x^2}-\frac {2 a^2 b^3 c^4}{x}+b^5 c^4 x-3 a b^4 c^4 \log (x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=-\frac {a^5 c^4}{4 x^4}+\frac {a^4 b c^4}{x^3}-\frac {a^3 b^2 c^4}{x^2}-\frac {2 a^2 b^3 c^4}{x}+b^5 c^4 x-3 a b^4 c^4 \log (x) \]
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Time = 0.37 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.79
method | result | size |
default | \(c^{4} \left (b^{5} x -3 a \,b^{4} \ln \left (x \right )+\frac {a^{4} b}{x^{3}}-\frac {2 a^{2} b^{3}}{x}-\frac {a^{3} b^{2}}{x^{2}}-\frac {a^{5}}{4 x^{4}}\right )\) | \(57\) |
risch | \(b^{5} c^{4} x +\frac {-2 a^{2} b^{3} c^{4} x^{3}-a^{3} b^{2} c^{4} x^{2}+a^{4} b \,c^{4} x -\frac {1}{4} a^{5} c^{4}}{x^{4}}-3 a \,b^{4} c^{4} \ln \left (x \right )\) | \(71\) |
norman | \(\frac {b^{5} c^{4} x^{5}+a^{4} b \,c^{4} x -\frac {1}{4} a^{5} c^{4}-2 a^{2} b^{3} c^{4} x^{3}-a^{3} b^{2} c^{4} x^{2}}{x^{4}}-3 a \,b^{4} c^{4} \ln \left (x \right )\) | \(73\) |
parallelrisch | \(-\frac {12 a \,b^{4} c^{4} \ln \left (x \right ) x^{4}-4 b^{5} c^{4} x^{5}+8 a^{2} b^{3} c^{4} x^{3}+4 a^{3} b^{2} c^{4} x^{2}-4 a^{4} b \,c^{4} x +a^{5} c^{4}}{4 x^{4}}\) | \(77\) |
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Time = 0.22 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.07 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=\frac {4 \, b^{5} c^{4} x^{5} - 12 \, a b^{4} c^{4} x^{4} \log \left (x\right ) - 8 \, a^{2} b^{3} c^{4} x^{3} - 4 \, a^{3} b^{2} c^{4} x^{2} + 4 \, a^{4} b c^{4} x - a^{5} c^{4}}{4 \, x^{4}} \]
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Time = 0.15 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.04 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=- 3 a b^{4} c^{4} \log {\left (x \right )} + b^{5} c^{4} x + \frac {- a^{5} c^{4} + 4 a^{4} b c^{4} x - 4 a^{3} b^{2} c^{4} x^{2} - 8 a^{2} b^{3} c^{4} x^{3}}{4 x^{4}} \]
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Time = 0.21 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.99 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=b^{5} c^{4} x - 3 \, a b^{4} c^{4} \log \left (x\right ) - \frac {8 \, a^{2} b^{3} c^{4} x^{3} + 4 \, a^{3} b^{2} c^{4} x^{2} - 4 \, a^{4} b c^{4} x + a^{5} c^{4}}{4 \, x^{4}} \]
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Time = 0.29 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=b^{5} c^{4} x - 3 \, a b^{4} c^{4} \log \left ({\left | x \right |}\right ) - \frac {8 \, a^{2} b^{3} c^{4} x^{3} + 4 \, a^{3} b^{2} c^{4} x^{2} - 4 \, a^{4} b c^{4} x + a^{5} c^{4}}{4 \, x^{4}} \]
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Time = 0.38 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.83 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^5} \, dx=-\frac {c^4\,\left (a^5-4\,b^5\,x^5+4\,a^3\,b^2\,x^2+8\,a^2\,b^3\,x^3-4\,a^4\,b\,x+12\,a\,b^4\,x^4\,\ln \left (x\right )\right )}{4\,x^4} \]
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